Find range of a reciprocal function given domain

$\begingroup$

I cannot find the range of this reciprocal function: 1/(x+1) whose domain is{x:x≥0, x a real number}.

I could draw the graph of this function but my confusion is if x-values are getting bigger from 0, then y-values are getting closer to 0 or approaching infinity, which means y-values are not getting bigger as x-values get bigger. Then how do I write the range?

Thanks in advance.

$\endgroup$

1 Answer

$\begingroup$

The $y$ values cannot approach $\infty$, the maximum value of $y$ is $1$ when $x=0$. As you say the function decreases, approaching $0$ but not getting there, so the range is $(0,1]$

$\endgroup$ 1

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password Submit

Post as a guest

Post Your Answer Discard

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy