Simplifying nested/complex fractions with variables

$\begingroup$

I have the equation $$x = \frac{y+y}{\frac{y}{70} + \frac{y}{90}} $$ and I need to solve for x. My calculator has already shown me that it's not necessary to know y to solve this equation, but I can't seem to figure it out. This is how I try to solve it: $$ x = \frac{y+y}{\frac{y}{70} + \frac{y}{90}} = 2y\left(\frac{70}{y} + \frac{90}{y}\right) = 2y\left(\frac{90+70}{y}\right) = 2y\cdot\frac{160}{y} = \frac{320y}{y} = 320 $$ But according to my calculator, this is not correct. The answer should be 78.75, but I don't know why. Any help would be much appreciated.

$\endgroup$ 5

3 Answers

$\begingroup$

When manipulating expressions, the most important thing is to think small. Find the smallest part of the expression you can do something with. In this case,

$$\frac{2y}{\frac{y}{70}+\frac{y}{90}}$$

has as the smallest available task add the fractions on the bottom, which gives (only showing that part)

$$\frac{y}{70}+\frac{y}{90}=\frac{90y+70y}{70\cdot 90}=\frac{160y}{6300}=\frac{8y}{315}$$

Putting that back in, we now have

$$\frac{2y}{\left(\frac{8y}{315}\right)}=2y\left(\frac{315}{8y}\right)=\frac{630y}{8y}=\frac{315}{4} \text{for } y\ne 0$$

$\endgroup$ 2 $\begingroup$

Dividing numerator and denominator by $y$ (assuming of course that $y \ne 0$),and multiplying them by $70$ and $90$, $$ x = \dfrac{2}{1/70 + 1/90} = \dfrac{2 \times 70 \times 90}{90 + 70} = \dfrac{12600}{160} = \dfrac{315}{4}$$

$\endgroup$ $\begingroup$

This is my solution:

$$ x=\frac{y+y}{\frac{y}{70}+\frac{y}{90}}={y}\cdot\frac{2}{{y}\cdot\left(\frac{1}{70}+\frac{1}{90}\right)}=\frac{2}{\frac{1}{70}+\frac{1}{90}}=\frac{2\cdot6300}{90+70}=12600/160=\boxed{78.75}$$

$\endgroup$

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password Submit

Post as a guest

Post Your Answer Discard

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy